Team India went on to make their redemption in second ODI at Rajkot after facing a crushing defeat at Wankhede. Almost all the players had a good hit-out but Rohit Sharma fell just short of a famous record at Rajkot but he will get his opportunity on Sunday.
Rohit Sharma started brilliantly on batting-friendly Rajkot deck. His elegant shots were coming out from the top drawer one after another. But then he misread a delivery from Adam Zampa and was declared LBW. Rohit Sharma fell just four runs short of 9000 marks in ODI cricket. He is currently at 8996 runs from 216 innings.
He is set to become third fastest to this mark, just behind Virat Kohli and AB de Villiers. He will be surpassing some of the greats of the game which includes Sourav Ganguly(228 innings), Sachin Tendulkar (235 innings) and Brian Lara (239 innings). Fans are expecting him to close down this record when he takes the field in the series decider at Bangalore on Sunday. Only Virat Kohli and AB de Villiers are ahead of him in the list with 194 innings and 205 innings respectively.
India were under pressure going into the game at Saurashtra Cricket Association Stadium in Rajkot. There were also talk about Indian batting order with all 3 openers playing in the team. But all fell into place with KL Rahul doing the role of a finisher in an exceptional way.
India made 340 with contributions from Shikhar Dhawan and Virat Kohli along with KL Rahul. Chasing the score, Australia lost Warner early with a screamer from Manish Pandey. Steve Smith played a great hand but it was not enough for Australia to avoid their first defeat in the last 3 months. Shami and Kuldeepwere instrumental in Indian bowling performance.